求【（2x³y-2x²y²）+xy（2xy-x²）】÷x²y的值

求【（2x³y-2x²y²）+xy（2xy-x²）】÷x²y的值
求【（2x³y-2x²y²）+xy（2xy-x²）】÷x²y的值

求【（2x³y-2x²y²）+xy（2xy-x²）】÷x²y的值
【（2x³y-2x²y²）+xy（2xy-x²）】÷x²y
=（2x³y-2x²y²）/x²y+xy（2xy-x²）/x²y
=2x-2y+2y-x
=x
楼主可能把(2xy-2x²)打成(2xy-x²)
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