作业帮已知x^2+y^2+5=2x+4y,求代数式[2x^2-(x+y)(x-y)][(x+y-1)(x-y-1)+1-2y]的值. 会给好评哦
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![已知x^2+y^2+5=2x+4y,求代数式[2x^2-(x+y)(x-y)][(x+y-1)(x-y-1)+1-2y]的值. 会给好评哦](/uploads/image/z/2430262-46-2.jpg?t=%E5%B7%B2%E7%9F%A5x%5E2%2By%5E2%2B5%3D2x%2B4y%2C%E6%B1%82%E4%BB%A3%E6%95%B0%E5%BC%8F%5B2x%5E2-%28x%2By%29%28x-y%29%5D%5B%28x%2By-1%29%28x-y-1%29%2B1-2y%5D%E7%9A%84%E5%80%BC.+++++++%E4%BC%9A%E7%BB%99%E5%A5%BD%E8%AF%84%E5%93%A6)
已知x^2+y^2+5=2x+4y,求代数式[2x^2-(x+y)(x-y)][(x+y-1)(x-y-1)+1-2y]的值. 会给好评哦
已知x^2+y^2+5=2x+4y,求代数式[2x^2-(x+y)(x-y)][(x+y-1)(x-y-1)+1-2y]的值. 会给好评哦
已知x^2+y^2+5=2x+4y,求代数式[2x^2-(x+y)(x-y)][(x+y-1)(x-y-1)+1-2y]的值. 会给好评哦
