计算:√4÷(1、2)ˆ-1+(-1)ˆ2013×4ˆ0x²+3x-1=0化简求值(x-y)/(x²-2xy+y²)-(xy-y²)/(x²-y²),其中(x-2)²+∣y-3∣=0

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计算:√4÷(1、2)ˆ-1+(-1)ˆ2013×4ˆ0x²+3x-1=0化简求值(x-y)/(x²-2xy+y²)-(xy-y²)/(x²-y²),其中(x-2)²+∣y-3∣=0

计算:√4÷(1、2)ˆ-1+(-1)ˆ2013×4ˆ0x²+3x-1=0化简求值(x-y)/(x²-2xy+y²)-(xy-y²)/(x²-y²),其中(x-2)²+∣y-3∣=0
计算:√4÷(1、2)ˆ-1+(-1)ˆ2013×4ˆ0
x²+3x-1=0
化简求值(x-y)/(x²-2xy+y²)-(xy-y²)/(x²-y²),其中(x-2)²+∣y-3∣=0

计算:√4÷(1、2)ˆ-1+(-1)ˆ2013×4ˆ0x²+3x-1=0化简求值(x-y)/(x²-2xy+y²)-(xy-y²)/(x²-y²),其中(x-2)²+∣y-3∣=0
√4÷(1/2)ˆ-1+(-1)ˆ2013×4ˆ0
=2÷2 +(-1)×1
=1 -1
=0
x²+3x-1=0
Δ=3²-4*1*(-1)=9+4=13
x=(-3±√13)/2
(x-y)/(x²-2xy+y²)-(xy-y²)/(x²-y²)
=(x-y)/(x-y)² - y(x-y)/[(x+y)(x-y)]
=1/(x-y) - y/(x+y)
已知(x-2)²+∣y-3∣=0,则有:
x-2=0且y-3=0
解得:x=2,y=3
所以所求式子=1/(x-y) - y/(x+y)=1/(2-3) - 3/(2+3)=-1 - 3/5=-8/5

计算:√4÷(1、2)ˆ-1+(-1)ˆ2013×4ˆ0
=2 ÷ 2 + (-1) * 1
= 1 -1 =0
x²+3x-1=0
b²-4ac=13
x= -(3+√13)/2或(√13-3)/2
(x-2)²+∣y-3∣=...

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计算:√4÷(1、2)ˆ-1+(-1)ˆ2013×4ˆ0
=2 ÷ 2 + (-1) * 1
= 1 -1 =0
x²+3x-1=0
b²-4ac=13
x= -(3+√13)/2或(√13-3)/2
(x-2)²+∣y-3∣=0
x=2,y=3
化简求值(x-y)/(x²-2xy+y²)-(xy-y²)/(x²-y²),其中
=(x-y)/(x-y)² - y(x-y)/(x-y)(x+y)
= 1/(x-y) - y/(x+y)
= 1/(-1) - 3/5
= -8/5

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计算:√4÷(1、2)ˆ-1+(-1)ˆ2013×4ˆ0
=2÷2+(-1)×1
=1-1
=0;
x²+3x-1=0
(x+3/2)²=1+9/4=13/4;
x+3/2=±√13/2;
x=-3/2±√13/2;
化简求值(x-y)/(x²-2xy+y²)-(x...

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计算:√4÷(1、2)ˆ-1+(-1)ˆ2013×4ˆ0
=2÷2+(-1)×1
=1-1
=0;
x²+3x-1=0
(x+3/2)²=1+9/4=13/4;
x+3/2=±√13/2;
x=-3/2±√13/2;
化简求值(x-y)/(x²-2xy+y²)-(xy-y²)/(x²-y²),其中(x-2)²+∣y-3∣=0
=(x-y)/(x-y)²-y(x-y)/(x+y)(x-y)
=1/(x-y)-y/(x+y)
x-2=0;
x=2;
y-3=0;
y=3;
原式=1/(2-3)-3/(2+3)
=-1-3/5
=-8/5;
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