x²+3x+2=(x-1)²+B(x-1)+C.求B,C

x²+3x+2=(x-1)²+B(x-1)+C.求B,C
x²+3x+2=(x-1)²+B(x-1)+C.求B,C

x²+3x+2=(x-1)²+B(x-1)+C.求B,C
(x-1)²+B(x-1)+C=x²-2x+1+Bx-B+C=x²+(B-2)+(1-B+C)=x²+3x+2;
B-2=3; B=5
1-B+C=2; C=6

令X=1 则6=C
代入得：（X+4）*（X-1）=（X-1）^2+B(X-1)
X+4=(X-1)+B
B=5