若(√x+1/2*x^(1/4))^n展开式的前三项系数成等差数列,求(1)展开式中所有的x的有理项（2）展开式中系数最大的项

若(x^2+1/x)^n(n∈N+,n x^(n)*x^(n+1)+x^(2n)*x (4x^n-2x^n-1-3x^n+2)÷（-5x^n-1) x^n-1(3x^n+4x^n+1-5x^n+2) 因式分解4x^(n+2)-9x^n+6x^(n-1)-x^(n-2) 因式分解4x^n+2-9x^n+6x^n-1-x^n-2 因式分解：x^(2n)+(2x)^(n)+4^(n-1) x^2n+(2x)^n+4^(n-1) 因式分解 (8x^n+1-3x^n-1)-2(-x+9x^n+1-4x^n)= 因式分解：(x^n+1)+(2x^n)+(x^n-1) x^n+1-2x^n+x^n-1因式分解 x^n-1-2x^n+x^n-1因式分解 分解因式x^n-x^(n-1)+x^(n-2) f(x)=e^x-x 求证(1/n)^n+(2/n)^n+...+(n/n)^n (-x)^3x^n-1+x^2n(-x)^3 x^n*x^n+1*(-x)^2n*x+(-x)^2n+3x^2n-2*x 4x^n+2-9x^n+6x^n-1-x^n-24x^(n+2)-9x^n+6x^(n-1)-x^(n-2),n是整数且大于2 x^n-2x^n+1,因式分解