1/4x^3y^2.(-2xy^2)+(-2x^2y).(-1/2xy).3xyz

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1/4x^3y^2.(-2xy^2)+(-2x^2y).(-1/2xy).3xyz

1/4x^3y^2.(-2xy^2)+(-2x^2y).(-1/2xy).3xyz
1/4x^3y^2.(-2xy^2)+(-2x^2y).(-1/2xy).3xyz

1/4x^3y^2.(-2xy^2)+(-2x^2y).(-1/2xy).3xyz
应该是{1/[4(x^3)(y^2)]}·[-2x(y^2)]+[-2(x^2)y]·[-1/(2xy)]·3xyz吧?
如果是的话：

{1/[4(x^3)(y^2)]}·[-2x(y^2)]+[-2(x^2)y]·[-1/(2xy)]·3xyz
=[-2x(y^2)]/[4(x^3)(y^2)]+[-2(x^2)y·(-3xyz)]/(2xy)
=(-1)/[2(x^2)]+3(x^2)yz
=3(x^2)yz-1/[2(x^2)]
=3(x^2)yz[2(x^2)]/[2(x^2)]-1/[2(x^2)]
={3(x^2)yz[2(x^2)]-1}/[2(x^2)]
=[6(x^4)yz-1]/[2(x^2)]

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