(1)lim[(x+1)(x-2)]/[(x-1)(3x-1)]=1/2(2)lim(2x+7)/[(x-1)(x+2)]=0(3)lim(3x^2+2x+1)/[(3x+1)(3x-1)]=1/3(4)lim(4x^2-4x+1)/(x^3+2x^2-2x+1)=0(5)lim(1+2^2+3^2+……+n^2)/n^3=1/3 提示：1^2+2^2+3^2+……+n^2=n(n+1)(2n+1)/6(6)lim(1+2+4+8+……+2^n)/2^n=1

来源：学生作业帮助网 编辑：作业帮 时间：2024/05/03 09:36:50
(1)lim[(x+1)(x-2)]/[(x-1)(3x-1)]=1/2(2)lim(2x+7)/[(x-1)(x+2)]=0(3)lim(3x^2+2x+1)/[(3x+1)(3x-1)]=1/3(4)lim(4x^2-4x+1)/(x^3+2x^2-2x+1)=0(5)lim(1+2^2+3^2+……+n^2)/n^3=1/3 提示：1^2+2^2+3^2+……+n^2=n(n+1)(2n+1)/6(6)lim(1+2+4+8+……+2^n)/2^n=1

(1)lim[(x+1)(x-2)]/[(x-1)(3x-1)]=1/2(2)lim(2x+7)/[(x-1)(x+2)]=0(3)lim(3x^2+2x+1)/[(3x+1)(3x-1)]=1/3(4)lim(4x^2-4x+1)/(x^3+2x^2-2x+1)=0(5)lim(1+2^2+3^2+……+n^2)/n^3=1/3 提示：1^2+2^2+3^2+……+n^2=n(n+1)(2n+1)/6(6)lim(1+2+4+8+……+2^n)/2^n=1
(1)lim[(x+1)(x-2)]/[(x-1)(3x-1)]=1/2
(2)lim(2x+7)/[(x-1)(x+2)]=0
(3)lim(3x^2+2x+1)/[(3x+1)(3x-1)]=1/3
(4)lim(4x^2-4x+1)/(x^3+2x^2-2x+1)=0
(5)lim(1+2^2+3^2+……+n^2)/n^3=1/3
提示：1^2+2^2+3^2+……+n^2=n(n+1)(2n+1)/6
(6)lim(1+2+4+8+……+2^n)/2^n=1
请帮忙看看以上各式的解答是否正确,数学极限是我自学的,不知掌握的怎样,如有不对,还请指教,小女在此先谢谢了!

(1)lim[(x+1)(x-2)]/[(x-1)(3x-1)]=1/2(2)lim(2x+7)/[(x-1)(x+2)]=0(3)lim(3x^2+2x+1)/[(3x+1)(3x-1)]=1/3(4)lim(4x^2-4x+1)/(x^3+2x^2-2x+1)=0(5)lim(1+2^2+3^2+……+n^2)/n^3=1/3 提示：1^2+2^2+3^2+……+n^2=n(n+1)(2n+1)/6(6)lim(1+2+4+8+……+2^n)/2^n=1
(1)lim[(x+1)(x-2)]/[(x-1)(3x-1)]=1/3
(6)lim(1+2+4+8+……+2^n)/2^n=lim [2^(n+1) - 1]/2^n=2
其他正确

lim(1-x)^(2/x) x->0 极限：lim(x->2)1/(x-2) lim(1-(5/x))^x-2 lim(x+e^2x)^(1/sinx) Lim(x>1) x-1/x^2+x-2.计算 lim x→1 x-1/x^2-x lim(x^2+1/x^2-2x)^x=? lim(x->无穷大){(2^x-3^x)/2}^(1/x) Lim [x^2/(x^2-1)]^x (x→∞) lim x->正无穷大 x ( sqrt(x^2+1)-x ) lim(x->0)((2-x)/(3-x))^1/x lim(1+x/x)2x (x→∞) lim(x→0)e^x-x-1/x^2 lim(x+1/x+2)^x=?x趋于无穷 lim(x趋于无穷)(x/1+x)^(x+2)=? X趋于0 Lim(xlnx)=Lim(lnx/(1/x))=Lim(1/x/(-1/x^2))=Lim(-x)=0Lim(lnx/(1/x))=Lim(1/x/(-1/x^2))其中这步使怎么转化的? (1) lim(x->正无穷) x-lnx (2) lim(x->0+) cosx^1/x^2 lim（x-3/x+1）^x lim趋向无穷大