int t,a=5,b=6,w=1,x=2,y=3,z=4;经过t=(a=w>x)&&(b=y+z)后,变量t,a,b分别为多少?

来源:学生作业帮助网 编辑:作业帮 时间:2024/05/06 10:06:31
int t,a=5,b=6,w=1,x=2,y=3,z=4;经过t=(a=w>x)&&(b=y+z)后,变量t,a,b分别为多少?

int t,a=5,b=6,w=1,x=2,y=3,z=4;经过t=(a=w>x)&&(b=y+z)后,变量t,a,b分别为多少?
int t,a=5,b=6,w=1,x=2,y=3,z=4;经过t=(a=w>x)&&(b=y+z)后,变量t,a,b分别为多少?

int t,a=5,b=6,w=1,x=2,y=3,z=4;经过t=(a=w>x)&&(b=y+z)后,变量t,a,b分别为多少?
根据优先级
w>x 1>2为假,所以w>x表达式的值为0,所以a=0
由于&&运算符的逻辑短路特性,&&左侧表达式值为假,那么整个表达式为假,右边表达式(b=y+z)不执行
所以a=0,t=0,b=6

int t,a=5,b=6,w=1,x=2,y=3,z=4;经过t=(a=w>x)&&(b=y+z)后,变量t,a,b分别为多少? void fun(int a,int b) { int t; t=a;a=b;b=t; } main()void fun(int a,int b){ int t; t=a;a=b;b=t; } main() { int c[10]={1,2,3,4,5,6,7,8,9,0}.i; for(i=0;i #include void main( ) { int a=3,b=5; int *p,*q; void f1(int x,int y);void f2(int *x,int *y);p=&a; q=&b;f1(*p,*q) ;printf(a=%d ,b=%d ,a,b);f2(p,q);printf(a=%d ,b=%d ,a,b);}void f1(int x,int y) { int t;t=x; x=y; y=t;}void f2(int *x,int *y) { int 下列方法定义中,正确的是()A.int x(int a,b){return (a-b);}B.double x(int a,int b){int w; w=a-b;}C.int x(int a,int b){return a-b;}D.double x(a,b){return b;} 改错题:共有5处错误#include #define N 15int move(int w,int p,int n){ int i,j,t;for(i=p;i=0;j--) w[j+1]=w[j]; w[0]=t;}void main(){ int k; int a[N];printf( lnput data:);for(k=0;k #include void fun(int a,int b) {int t; t=a;a=b;b=t; } main() {int c[6]={1,2,3,4,5,6},i;for(i=0;i #include void fun(int a, int b) { int t; t=a; a=b; b=t;main() { int c[10]={1,2,3,4,5,6,7,8,9,0), i; for (i=0; i #include stdio.h void fun(int a,int b) { int t; t=a,a=b,b=t; } main() { int c[10]={1,2,3,4,5,6,7#include stdio.hvoid fun(int a,int b){int t;t=a,a=b,b=t;}main(){int c[10]={1,2,3,4,5,6,7,8,9,0},i;for(i=0;i C语言程序,求3个整数的最大值.#include void main(){int max(int x,int y,int z);int a,b,c;scanf(%d%d%d,&a,&b,&c);d=max(a,b,c);printf(max=%d,d);}int max(int x,int y,int z){int w;if (x>y) w=x;else w=y;if (w>z) max=w;else max=z;return (max); Int w = 'A',x = 14,y = 15; W = ((x || y) && (w < 'a' )); A.-1 B.NULL C.1 D.0 执行以下语句后A的值是int a=5,b=6,w=1,x=2,y=3,z=4(a=w>x)&&(b=y>z) 求助MATLAB符号计算:%声明符号变量syms c w t b a D n T v Q x y;%给已知的变量赋值D=0.038;w=2*pi/T;v=n*w*D/2;%正切值b= (sin (w*t))/(c-cos (w*t));%余弦值a=sqrt (1/ (1+b^2));%正弦值d=sqrt ((b^2)/ (1+b^2));x=int (v*sqrt (1/ (1 下列数组定义错误的是 A.int x=5,a[x]; B.int aa[1]; C.int aa[2][3]; D.int a['a']; #includeint a(int x);int b(int y);int main(){int m,n;n=6;m=a(n);printf(%d ,m);return 0;}int a(int x){x=b(x+3);return x;}int b(int y){return y+1;} int a=5,b=1,t; t=(a int w= A ,x=14,y=15; W=((x||y)&&(w< a )); w的值? int w[3][4]={{0,1},{2,4},{5,8}}; int (*p)[4]=w; 则数值为4的表达式是int w[3][4]={{0,1},{2,4},{5,8}};int (*p)[4]=w;则数值为4的表达式是 .(A)*w[1] (B)*p[1] (C) w[2][2] (D)p[1][1] void swap1(int c0[],int c1[]) { int t; t=c0[0];c0[0]=c1[0];c1[0]=t; } void swap2(int *c0,int *c1) {void swap1(int c0[],int c1[]){ int t;t=c0[0];c0[0]=c1[0];c1[0]=t;}void swap2(int *c0,int *c1){int t;t=*c0;*c0=*c1;*c1=t;}void main(){int a[2]={3,5},b[