log8 (log2 4根号2)的值是是log8*(log(2 4根号2))

log8 (log2 4根号2)的值是是log8*(log(2 4根号2)) 求（log2^3+log8^9)(log3^4+log9^8+log3^2)的值 log8 4=?2^(log2 3-2)=? (log4^3+log8^3)*(log3^2+log9^2)-log2^4次√32(log4^3+log8^3)*(log3^2+log9^2)-log2^(4√32)（那个4是根号上的）（log旁边的数字是在最下面的） 已知log2（log8^m)=log8(log2^m),求log2^m的平方 若log2(log8 m)=log8(log2 m),则(log2 m)^2 log8的27除以log2的3 log8^9/log2^3的值是 (log4＾3+log8＾3)(log3＾2+log9＾2)+log2＾(32)的1/4次方 [log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2)][log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2) log2的三/log8的九的值是A3/2 B1 C2/3 D2 log3^36-log3^4+log2(log2^16)+8^2/3+(27/8)^-1/3+log8^27/log4^9怎么算啊,不好意思哦,我已经没分啦.麻烦一下写一写log2(log2^16) (27/8)^-1/3 log8^27/log4^9 （log8 9） /（log2 3）的值.8和2是底数. (log2(3)+log8(9))x(log3(4)+log9(8)+log3(2)) 求值：(log4(3)+log8(3))(log3(2)+log3(4))-log2(64) [log2 (125) +log4(25)+log8(5)][log125(8)+log25(4)+log5(2) (Log2 125+log4 25+log8 5)(log5 2+log25 4+log125 log8(9)*log2(3)