log4(12)与log8(27)的差和log4(27)与log2(6)的差的比值为

log4(12)与log8(27)的差和log4(27)与log2(6)的差的比值为 (log8^27)/(log4^9)的值 log4(3)-log4(12)-log8(4) =log4(3/12)- log8( 8^(2/3) ) log8( 8^(2/3) )怎么得出来的? 1.log18/25(2/5)2.log4 27×log8 25×log9 5( 8和25是上下并列写的, log4 243 - log8 729=?log4 12 - log2 6=? 化简：（log2(3)+log4(9)+log8(27)+…+log2n(3^n))*log2(8的n次方根) (log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根 (log2 3+log4 9+log8 27+...+log2^n 3^n）log9 32的N次方根 log4 8-log8 4=? log4 3和log8 3是通过哪条法则转换成（1/2)log2 3和（1/3)log2 3的? 已知½log8（a）+log4（b）=5/2,log8(b)+log4(a^2)=7 求ab的值 (log4的三次方+log8的三次方)(log3的2次方-log9的二次方) log4^25+log8^8/125,最后的答案是等于一的, 求(log3^2 + log9^2)×（log4^3 + log8^3)的值.请给出过程,谢谢! 化简log3(4)*log4(5)*log5(8)*log8(9)的结果是? log4(3)+log8(3) 怎么算 log4(3)+log8(3) 怎么相加? log4 2+log8 2=多少?