sin(arccos1/4)=?

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sin(arccos1/4)=?
sin(arccos1/4)=?

sin(arccos1/4)=?
令 x =arccos (1/4),
则 x ∈(0,π),
且 cos x =1/4.
所以 sin x =√ [ 1 -(cos x)^2 ]
= √15 /4.
即 sin [ arccos (1/4) ] = √15 /4.
= = = = = = = = =
换元法.
注意 f(u) =arccos u 的值域.
arccos

cosa=1/4,sina=√15/4
sin(arccos1/4)=sin(arcsin√15/4)=√15/4

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