记等差数列an的前n项和为Sn,若S2n-1=(2n-1)(2n+1),则Sn=?怎么解

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记等差数列an的前n项和为Sn,若S2n-1=(2n-1)(2n+1),则Sn=?怎么解

记等差数列an的前n项和为Sn,若S2n-1=(2n-1)(2n+1),则Sn=?怎么解
记等差数列an的前n项和为Sn,若S2n-1=(2n-1)(2n+1),则Sn=?怎么解

记等差数列an的前n项和为Sn,若S2n-1=(2n-1)(2n+1),则Sn=?怎么解
另k=2n-1 然后n就等于 (k+1)/2 把 (k+1)/2带入n 求出来